Question

A body of mass 500g is at rest on a frictionless surface. What is the distance travelled by it in 10s when acted upon by a force of 10 N? first correct answer will marked brainliest.

Answer 1

Answer:

distance travelled in 10 sec=1 meter

Explanation:

A body of mass 500 g is at rest on a frictionless surface.

When the body is acted upon by a force of 10^{-2}10

−2

N,

then find distance traveled by the body in 10 seconds .

Solution :

We know that,

Force = Mass × Acceleration ( F = ma )

Force (F) = 10^{-2}10

−2

N = 0.01 N

Mass (m) = 500 g = 0.5 kg

⇒ F = ma

⇒ 0.01 = 0.5a0.01=0.5a

⇒ \frac{0.01}{0.5} = a

0.5

0.01

=a ⇒ a = 0.02 m/s²

We also knew that,

Distance traveled (s) = ut + ¹/₂ at² (here , s meant distance travelled)

here u = 0 m/s

t = 10 seconds.

a = 0.02 m/s²

⇒ s = ut +\frac{1}{2} at^2s=ut+

2

1

at

2

⇒ s = 0 \times 10 +\frac{1}{2} \times 0.02 \times (10)^2s=0×10+

2

1

×0.02×(10)

2

⇒ s = 0 + 0.01 \times 100s=0+0.01×100 = 1 m

Answer 2

________________________________________________

Question :

A body of mass 500 g is at rest on a friction less surface. What is the distance traveled by it in 10 s when acted upon by a force of 10 N?

_________________________________________________

Given:

• mass of the body = 500 g = 0.5 kg
• time taken = 10 sec

• force = 10 N
• initial velocity = 0 m/s (as the object is at rest )

_______________________________________________

To find :

• distance traveled

_______________________________________________

Concept :

• First we need to find the acceleration of the body
• then use the second kinematics equation in order to find the distance traveled

__________________________________________________

Solution :

Force acting on the body is given by the formula ,

>> F= ma

here ,

• F= force
• m= mass
• a = acceleration

->10=0.5 x a

-> a = 10 /0.5

-> a = 20 m/s^2

----------------------------------------------------------------------------

By using the second kinematic equation ,

>> s= u t + a t^2 / 2

here ,

• s = distance

• u = initial velocity

• a= acceleration
• t = time taken

-> s = 0 x 10 + 20 x 100 /2

-> s = 10 x 100

-> s = 1000 m

Distance traveled by the body in 10 sec is 1000 m .

________________________________________________

Hope this helps :D