A body of mass 500g is at rest on a frictionless surface. Calculate rhe diatance travelled by it in 10s when acted upon by a force of 10 ^-2 N.
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Answer:
1 m
Explanation:
F = m×a
a = 10-²/0.5 = 2×10-²
as initially the body is at rest so u= 0 ( initial velocity)
S = ut + 1/2 at² (2nd law of motion)
S = 1/2 ×2×10-² ×10²
S = 1m
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