Physics, asked by parthivgsheth, 1 year ago

a body of mass 500g is resting on a frictionless surface. calculate the distance by it in 10 seconds when acted upon by a force of 10 2N

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Answered by govindsharmazerofour
1

I think it will help you

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Answered by Anonymous
2

\sf\huge{\underline{\underline{Solution}}}-

Here,

  • \sf{F = 0.01 N}
  • \sf{m = 500 g= 500/1000 kg= 0.5 kg}

\sf\red{F = ma}........................\red{(1)}

Substituting the values in Eqn. (1)

\sf{a = F/m}

\sf\: \: \:= 0.01 N/0.5 kg

\sf \: \: \:= 0.2 m/s²

\sf\red{S = ut + 1/2 at}²........................\red{(2)}

Here,

  • \sf{u = 0}
  • \sf{t = 10 s}
  • \sf{a = 0.2 m/s}²

Substituting the values in Eqn. (2)

\sf{S = 0 × 10 + (1/2)0.2 × (10)}²

\sf\: \: \:{= 1 × 0.01 × 100}

\sf\: \: \:={\boxed{\underline {\sf\red{1 m}}}}.

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