Question

A body of mass 500kg started from rest and covered a distance of 100 m in 5s. Then find force experienced by the body.​

Answer 1

Given

A body of mass 500 kg started from rest and moves with a speed of 10 m/s in 5 s

To Find

Force

Solution

We know that

$\rm \longrightarrow F=m \times a$

$\rm \longrightarrow a=\bigg(\dfrac{v-u}{t}\bigg)$

Therefore

$\rm \longrightarrow F=m \times \bigg(\dfrac{v-u}{t}\bigg)$

Here

F = Force

m = Mass

a = Acceleration

u = Initial velocity

v = Final velocity

t = Time

Units

F = Newton (N)

m = kilogram (kg)

a = metre/square second (m/s²)

u = metre/second (m/s)

v = metre/second (m/s)

t = second (s)

According to the question

We are asked to find the force

Therefore

We must find "F"

Given that

A body of mass 500 kg started from rest and moves with a speed of 10 m/s in 5 s

Hence

m = 500 kg

u = 0 m/s [starts from rest]

v = 10 m/s

t = 5 s

Substituting the values

We get

$\rm \longrightarrow F=500 \times \bigg(\dfrac{10-0}{5}\bigg) \ N$

$\rm \longrightarrow F=500 \times \bigg(\dfrac{10}{5}\bigg) \ N$

$\rm \longrightarrow F=100 \times 10 \ N$

Therefore

$\rm \longrightarrow F=1000 \ N$

Hence

Force = 1000 N