Question

A body of mass 50g has a heat capacity of 3cal/°C. What will be the specific heat capacity of that body

Answer 1

Answer:

Let subscript 1 denote solid (hot body) and subscript 2 denote water (cold body)

Initial temp. of solid T₁=150°C

Mass of solid m₁ = 50 g = 0.05 Kg

Initial temp. of water T₂=11°C

Mass of water m₂= 100 g = 0.1 Kg

Final temp of both T= 20°C

Specific heat capacity of water c₂=4.2 J/g°C 

Let Specific heat capacity of solid be c₁

now,

heat gained by water = heat lost by solid

heat gained/lost = mcΔT

∴ m₁c₁ΔT₁ = m₂c₂ΔT₂

⇒ 0.05*c₁*(150-20) = 0.1*4.2*(20-11)

⇒ 0.05*130*c₁ = 0.1*4.2*9

⇒ c₁ = 0.5815 J/g°C

Answer: Specific heat capacity of the solid is 0.5815 J/g°C .

Explanation: