Question

a body of mass 50g is at rest on a smooth surface. a force of0.3N act on it for 10sec. calculate at the distance travelled by the body.
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Answer 1

Answer:

the distance is travelled by the body is 25 m

Answer 2

→Answers :

Brainly.in

Answer: The distance travelled

25m

Given that mass = 100g = 0.1kg

Weight = m \times g = 100 \times 10= 1000 N

Force applied F = 0.2 N

Time (t) = 5 sec

Initial velocity (u) = 0

We now that

Fore = mass \times acceleration

0.2 = 0.1 \times a

=> a = 2 m/sec^2

S\quad =\quad ut+\frac { 1 }{ 2 } a{ t }^{ 2 }

S = 0 + 0.5 \times 2 \times (5)^2

S = 0.5 \times 2 \times 25 = 25 m

Therefore, distance traveled by the body = 25 m