Question

a body of mass 50g is moving with a velocity of 10m/s . it is bought to rest by a resistive force of 10N . Find the distance that the body will travel after the resistive is apply

Answer 1

Given

m = 50g = 50*10^-3kg

u = 10m/s

F=10N

Let v be 0

Now by F = ma

a = F/m

= 10/50*10^-3

=200m/s^2

NOW ACCORDING TO FORMULA,

v^2 -u^2 = 2as

0 - 10^2 = 2*(-200)s (AS IT IS RETARDITION)

s = 0.25m = 25cm.

CONGRATS! :)

Answer 2

Force = mass×accelaration
10N=0.05a(50/1000;i.e 1000g = 1kg)
10=5a/100
10(100)=5a
1000=5a
1000/5=a
a=200m/s^2
v^2-u^2=2as
(0)^2-(10)^2=2(-200)s(since it is retardation)
-100=-400s
-100/-400=s
s=0.25m