Question

A body of mass 50kg is kept on a
horisontal suyace of coefficient of faks
is 0.5 find the least horizontal
torce required to start to motion . If
now the body is slightly, disturbed and
the same for ce continues to act find
the acclesation with which it moves.
Coeffficenr of kinetic friction is (0.48)
​

Answer 1

Explanation:

Here , maximum value of static friction that can act on the body = μ

mg = 25 N

(i) Since the applied force is less than the maximum possible value of static friction

therefore , the force of friction will be just enough to stop the motion of the body.

Here , friction force = 15 N

(ii) Here, applied force = maximum possible value of static friction.

Friction force = 25 N

(iii) Here , applied force > maximum value of static friction.

Therefore , the body moves and kinetic friction acts on the body.

Friction force = μ

k

mg = 20 N.

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