Question

A body of mass 50kg performs work of 2.5kj applying certain force. the distance covered by body in 2 seconds is....?.​

Answer 1

Answer:

Given mass= 2 kg and time period fro simple harmonic motion= 4 s.

We know Time period T of mass m on a spring of spring constant 'k'=2π

k

m

T=2π

k

m

k=

16

4π

2

m

=4.93N

ALso Force=mass×accelerationduegravity=kx -----1

where x is the displacement

Also potential energy of the spring is given as

=

2

1

kx

2

Now from 1

x

4.93

2×10

=4.05m

Thus potential enrgy stored in the spring

=

2

1

(4.93×4.05

2

)=40.43J

Explanation:

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