Question

a body of mass 5kg explodes at rest into three fragments with masses in to the ratio 1:1:3. the fragments with equal masses fly in mutually perpendicular directions with speeds of 21m/s. the velocity of heaviest fragment in m/sec will be what?

Answer 1

Masses of the pieces are 1, 1,3 kg. 

Hence,

(1 × 21)2 + (1 × 21)2 = (3 × V)2 

That is,

V = 7 √2.

Answer 2

Explanation:

momentum of both the masses of 1 kg are

• 1st body 1×21=21
• 2nd bady 1×21=21

their resultant 21root 2

then you apply conservation of linier momentum