A body of mass 5kg has momentm of 10kgm/s when a force of 0.2n is applied on it for 10sec wat is change in its kinetic energy
Answers
Answered by
1
ஏFinal momentum p2 = Ft+ p1 , p1 is the initial momentum.
p2 =0.2*10 + 10 = 12 kg-m/s.
Increase in kinetic energy = (p2^2 - p1^2)/2m
= ( 12^2 - 10^2)/ (2*5) = (12 +10) (12-10) /10 = 4 .4 J
p2 =0.2*10 + 10 = 12 kg-m/s.
Increase in kinetic energy = (p2^2 - p1^2)/2m
= ( 12^2 - 10^2)/ (2*5) = (12 +10) (12-10) /10 = 4 .4 J
Similar questions