A body of mass 5kg having a velocity 80m/s experience a force in the opposite direction. The body is brought to rest in 8sec .what is the retardation produced by the force?
Answers
Answered by
1
Answer:
retardation=change in velocity/time taken
= final velocity-initial velocity/time taken
=80-0/8(as the object stops hence final
=10m/s velocity will be 0)
Answered by
3
Answer:
Let,
m=5 kg
v= 80 m/s
u= 0 m/s
t= 8 seconds
a = v-u/t
a= 80 - 0/ 8
a=10 m/s
Therefore, retardation =10 m/sec
Step-by-step explanation:
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