Question

A body of mass 5kg having a velocity 80m/s experience a force in the opposite direction. The body is brought to rest in 8sec .what is the retardation produced by the force?
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Answer 1

Answer:

retardation=change in velocity/time taken

= final velocity-initial velocity/time taken

=80-0/8(as the object stops hence final

=10m/s velocity will be 0)

Answer 2

Answer:

Let,

m=5 kg

v= 80 m/s

u= 0 m/s

t= 8 seconds

a = v-u/t

a= 80 - 0/ 8

a=10 m/s

Therefore, retardation =10 m/sec

Step-by-step explanation: