Question

A body of mass 5kg , initially at rest , is moved by a horizontal force of 2 N on a smooth horizontal surface. Find the work done by the force in 10 s.?

Answer 1

ANSWER

w=40 J

Explanation:

a=F/m

a=2/5 m/s²

s=1/2at² ( because u is zero)

s=1/2*2/5*10²

s=2/10*100

s=20m

w=F.S

w=2*20

w=40 J

Answer 2

Answer:

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