Question

A body of mass 5kg initially at rest is subjected to a force of 20N what is the kinetic energy acquired by the body at the end of 10 seconds

Answer 1

hey

Force = mass × acceleration

A= F/m

a= 4 m/s ².

We know that,
$Kinetic \: \: \: energy = \frac{1}{2} m {v}^{2}$

To find v:-

V= u+at 

V= 0+40 
V= 40 m/s.

Kinetic energy = 1/2 ×5×40×40

Kinetic energy =4000 J.

Hope it helps to you.

Answer 2

Hey! ! !

Mate :-

Solution :-

Given :-

☆ m = 5 kg

☆ F = 20 N

☆ t = 10 sec

:- ke = 1/2mv*2

:- a = ( v - u)/t

:- F = m a

a = F/m = 20/5

:- a = 4 m/s*2

=> V = at = 4 × 10 = 40 m/s

:- 1/2mv^2 = 1/2× 5× 40×40

= 5× 20 × 40
= 100×40
= 4000 j Ans

☆ ☆ ☆ Hop its helpful ☆ ☆ ☆

☆ Regards :- ♡♡《 Nitish kr singh 》♡♡