A body of mass 5kg initially at rest is subjected to a force of 20N find the k.E acquired by the body at the end of 10 sec
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Force is ma=20
Hence, a=20/m=20/5=4
Now u=0,
v=u+at
v=0+(4*10)=40
Now KE=1/2mv^2
KE=1/2*5*40*40=4000
Hence, a=20/m=20/5=4
Now u=0,
v=u+at
v=0+(4*10)=40
Now KE=1/2mv^2
KE=1/2*5*40*40=4000
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