Question

A body of mass 5kg initially rest upon by two mutually perpendicular force 12N and 5N . If the particles moves in the direction of OA , calculate the magnitude of the acceleration

Answer 1

Explanation:

mass = 5kg

The forces acting on the body are 12N and 5N which are at an angle of 90°

• The resultant force of two forces acting at an angle theta

1. =
2. $\sqrt{(} f1) {}^{2} + (f2) {}^{2} + (f1)(f2)(cos theta)$

where F1 and F2 are the forces

Now cos theta = cos 90 = 0

so for two forces acting perpendicularly

we can directly take as ✓(F1²+F2²)

=✓(12²+5²) = ✓(169) = 13N

acceleration = Force/mass

= 13/5= 2.6 m/s²