Physics, asked by kranjna555oxa8gk, 1 year ago

A body of mass 5kg is acted upon two perpendicular forces of magnitude 8N and 6N. Find the magnitude and direction of acceleration.

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Answered by insiyahr

Net force, F 2=82+62 N
F2=100 N and hence, F= 10N
Acceleration, a = F/m= 10/5= 2m/s2
If the net force F makes an angle beta(b) with the horizontal, then the acceleration will also make an angle beta (b) with the horizontal . this is because the acceleration is always in the direction of force.
Tan b =6/8 =3/4 = 0.75
Hence, b = tan-1(0.75)= 36.9o

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Answered by QueenOfKnowledge

Answer:

Net force, F 2=82+62 N

F2=100 N and hence, F= 10N

Acceleration, a = F/m= 10/5= 2m/s2

If the net force F makes an angle beta(b) with the horizontal, then the acceleration will also make an angle beta (b) with the horizontal . this is because the acceleration is always in the direction of force.

Tan b =6/8 =3/4 = 0.75

Hence, b = tan-1(0.75)= 36.9o

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