A body of mass 5kg is initial at rest. Due to application of external force of 20N it accelerates. Determine its
1) Velocity in 3 sec
2) Displacement in 3 sec
3) It linear momentum
4) Kinetic energy
Answers
Answer:
1) 12 m/s
2) 18 m
3) 60 kg m/s
4) 360 J
Explanation:
Given:
Mass of the body (m) = 5 kg
Initial velocity (u) = 0 m/s (as it was at rest)
Force applied (F) = 20 N
First, we need to find the acceleration (a) of the body.
F = ma (Newton's 2nd Law Of Motion)
⇒ 20 = 5a
⇒ a = 20/5
⇒ a = 4 m/s²
1) Velocity in 3 Seconds
We can find its final velocity (v) in 3 seconds by using the 1st formula of motion.
v = u + at
⇒ v = 0 + (4*3)
⇒ v = 12 m/s
2) Displacement in 3 Seconds
We can find its displacement (s) in 3 seconds by using the 3rd formula of motion.
v² = u² + 2as
⇒ 12² = 0 + (2*4*s)
⇒ 144 = 8s
⇒ s = 144/8
⇒ s = 18 m
3) Linear momentum (p)
p = mv
⇒ p = (5 * 12)
⇒ p = 60 kg m/s
4) Kinetic Energy (KE)
K.E = 1/2mv²
⇒ K.E = 1/2 * 5 * 12 * 12
⇒ K.E = 360 Joules
Hope it helps!
Given : A body of mass 5kg is initial at rest
Due to application of external force of 20N it accelerates.
To Find :
1) Velocity in 3 sec
2) Displacement in 3 sec
3) It linear momentum
4) Kinetic energy
Solution:
m = 5 kg
u = 0
F = 20 N
F = ma
=> 20 = 5a
=> a = 4 m/s²
V = u + at
Velocity at 3 secs
= 0 + 4(3)
= 12 m/s
Displacement in 3 sec
S = ut + (1/2)at²
=> S = 0 + (1/2)4(3)²
=> S = 18 m
Linear Momentum = mv
= 5 (12)
= 60 kgm/s or Ns
Kinetic energy = (1/2)mv²
= (1/2)5(12)²
= 360 J
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