Question

A body of mass 5kg is moving with a uniform velocity of 10m/s.It is acted upon a force of 20N.What will be its velocity after 1second?

Answer 1

F=ma
20=5*a
20/5=a
4=a
a=v-u/t
4=v-0/1
4= v
velocity after 1 sec=4 m/s

Answer 2

Answer:

Explanation:

Given :-

Mass of the body, m = 5 kg

Initial speed of a body, u = 10 m/s

Time taken by the body, t = 1 seconds

Force exert on the body, F = 20 Newton

To Find :-

Final speed, v = ??

Formula to be used :-

Force = mass × acceleration

1st equation of motion i.e v = u+ at

Solution :-

Putting all the values, we get

Force = Mass × Acceleration

⇒ Acceleration = Force / mass

⇒ Acceleration = 20N / 5kg

⇒ Acceleration = 4 m/s².

Putting Acceleration value in v = u+ at, we get

⇒ v = u+ at

⇒ v = 10+(4)(1)

⇒ v = 14 m/s

Hence, the velocity after 1 second is 14 m/s.