Question

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A body of mass 5kg is moving with a velocity of 10 m/s what will be the ratio of its initial kinetic
energy and final kinetic energy. if the mass of the body is doubled and its velocity is halved.​

Answer 1

Answer:

Explanation:

Initial kinetic energy = 1/2*m*v^2 = 1/2 * 5*100 = 250J

Now, mass is doubled and velocity is halved

Final kinetic energy = 1/2* 2m*(1/2v)^2 = 1/2 * 10 * 25 = 125J

Ratio of initial to final = 250/125 = 2

Another way to do it would be

Ratio = $1/2  * mv^2/(1/2  * 2m *v^2)$

The 1/2 on the top and bottom can be cancelled, the m can be cancelled, and the v^2 can be cancelled, leaving you with$1/2*1/4 = 1/2$

Thats the answer

Answer 2

The ratio of initial kinetic energy and final kinetic energy is 2:1

Explanation:

• Kinetic energy of any object is the energy possessed by virtue of its motion it depends on mass and velocity of the body. For constant mass of the object if velocity of the body is increased its energy will also increases or vice- versa

Given, mass of the body = 5 kg

velocity of body = 10 m/s

Kinetic energy = $\frac{1}{2} mv^{2}$

=> Initial kinetic energy = $\frac{1}{2} 5(10)^{2}$

=> Initial kinetic energy = 250 J        .........................(1)

another case, mass of the body = 10 kg (double the original mass)

velocity of the body = 5 m/s (half of the original velocity)

=> Final kinetic energy = $\frac{1}{2} 10(5)^{2}$

=> Final kinetic energy = 125 J           .............................(2)

Ratio of kinetic energy = $\frac{initial K.E}{final K.E}$

=> Ratio = $\frac{250}{125}$

=> Ratio = 2:1

To know more about kinetic energy, visit:

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