a body of mass 5kg is moving with a velocity of 10m/s.A force is applied to it so that in 25 seconds, it attains a velocity of 35m/s.calculate the value of force applied
Answers
Answered by
238
hey mate here is your answer
f=ma
given,m=5kg a=(u=10m/s v=35m/s t=25sec)=(v-u)/t =(35-10)/25=1
f=ma
f=5*1=5N(Ans)
hope this will help you
please mark me brainlist
f=ma
given,m=5kg a=(u=10m/s v=35m/s t=25sec)=(v-u)/t =(35-10)/25=1
f=ma
f=5*1=5N(Ans)
hope this will help you
please mark me brainlist
Answered by
15
Given:
m = 5kg
initial velocity = 10 m/s
time = 25 sec
final velocity = 35 m/s
To Find:
Force
Solution:
we know,
v - u = at
a = (v - u) / t
a = (35 - 10) / 25
a = 25 / 25 = 1 m/s²
now,
F = ma
F = 5 * 1 = 5N.
So, Force = 5N.
Similar questions