Question

A body of mass 5kg is moving with velocity 3m−1, then find its Kinetic energy

Answer 1

Explanation:

ANSWER

Let the velocity of the second body be v after collision.

Applying conservation of momentum: m

1

u

1

−m

2

u

2

=0+m

2

v

∴ 5×3−3×2=3v ⟹v=3 ms

−1

Loss in kinetic energy ΔK.E=

2

1

m

2

v

2

−(

2

1

m

1

u

1

2

+

2

1

m

2

u

2

2

)

∴ ΔK.E=

2

1

3(3)

2

−

2

1

5(3)

2

−

2

1

3(2)

2

=−15J

SEE THE IMAGE

Answer 2

this is the image click on the white space.

Answer:

ANSWER

Let the velocity of the second body be v after collision.

Applying conservation of momentum: m

1

u

1

−m

2

u

2

=0+m

2

v

∴ 5×3−3×2=3v ⟹v=3 ms

−1

Loss in kinetic energy ΔK.E=

2

1

m

2

v

2

−(

2

1

m

1

u

1

2

+

2

1

m

2

u

2

2

)

∴ ΔK.E=

2

1

3(3)

2

−

2

1

5(3)

2

−

2

1

3(2)

2

=−15J

Explanation:

SEE THE IMAGE