a body of mass 5kg is moving with velocity of 10m/s. a force is applied to it so that in 25sec it will attain a velocity of 35m/s calculate force
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Answered by
11
Hey here is ur solution
F=?
m=5kg
a=v/t
v=35m/s
t=25sec
F=ma
F=m×v/t
F=5×35/25
F=35/5
F=7 N
Please mark me as brillianist please.......
F=?
m=5kg
a=v/t
v=35m/s
t=25sec
F=ma
F=m×v/t
F=5×35/25
F=35/5
F=7 N
Please mark me as brillianist please.......
lpskshatri:
me inter 1st year
Answered by
4
m=5kg
u=10m/s
v=35m/s
t=25secs
acceleration (a) = (v-u)/t
= (35-10)/25
= 25/25
=1
now, force(f)=ma
=5×1
=5
force applied is 5 newton
u=10m/s
v=35m/s
t=25secs
acceleration (a) = (v-u)/t
= (35-10)/25
= 25/25
=1
now, force(f)=ma
=5×1
=5
force applied is 5 newton
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