Question

a body of mass 5kg is moving with velocity of 2 m/s comes to rest finds its change in momentum​

Answer 1

Answer:

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Explanation:

change in momentum (p) = mass (m) x velocity (v)

                                 p =  5 x 2

                              ∴p = 10 m/s

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Answer 2

$\huge\orange{\boxed{\mathcal{Question:-}}}$

A body of mass 5 kg is moving with a velocity of 2 metre per second then it comes to rest find the change in momentum .

$\huge\pink{\boxed{\mathcal{Solution:-}}}$

Given is that ,

The mass of the object = 5 kg

Intial velocity = 2 m / s

Final velocity = 0 m / s ( in rest )

We know that Momentum ( p ) = m × v ,

And therefore the change in momentum is mass into to the change in velocity .

Hence the change in momentum would be ,

$\hookrightarrow\:\bf\:mass\:×\:(v_f\:-\:v_u)$

Where , $v_f$ is the final velocity and $v_u$ is the intial velocity.

Therefore substituting the values we get ,

$\leadsto\:p\:=\:m\:\times\:(v_f\:-\:v_u)$

$\leadsto\:p\:=\:5\:\times\:(0\:-\:2)$

$\leadsto\:p\:=\:5\:\times\:( -\: 2 )$

$\leadsto\:p\:=\:-\:10\:kg\:m\:/\:s$

So magnitude of change in momentum is ,

$\leadsto\:|m|\:=\:|-10|\:$

$\leadsto\:m\:=\:10\:$