A body of mass 5kg is moving with velocity of 20m/s. A force is applied on the body for 25s and it attains velocity of 40m/s. What is the force applied?
Answers
Answered by
7
as we know...
F=MA
here,
mass=5kg
initial velocity (u)=20m/s
final velocity (v)=40m/s
time(t)=25s
the formula can be rewritten as,
F=M (v-u/t)
therefore the solution is,
F=5x(40-20/25)
=20/5
=4N
therefore the total force applied on the body is 4 N .
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Answered by
8
Given ,
Mass = 5 kg
Initial velocity (u) = 20 m/s
Time (t) = 25 sec
Final velocity (v) = 40 m/s
We know that , the mathematical expression of acceleration is given by
a = (v - u)/t
a = (40 - 20)/25
a = 20/25
a = 4/5
a = 0.8 m/s²
We know that , the mathematical expression of force is given by
F = m × a
F = 5 × 0.8
F = 8/2
F = 4 Newton
Hence , The 4 newton force is applied
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