Question

A body of mass 5kg is placed on rough horizontal surface. If coefficients of static and kinetic friction are 0.5 and
0.4, then find value of force of friction when applied horizontal external force is 35N.

Please answer asap it's URGENT

ALSO DON'T SPAM! IF YOU DON'T KNOW THE ANSWER LEAVE IT AND MOVE ON!

THANKS IN ADVANCE.
​

Answer 1

Answer:

Here , maximum value of static friction that can act on the body = μ

s

mg

= 25 N

(i) Since the applied force is less than the maximum possible value of static friction

therefore , the force of friction will be just enough to stop the motion of the body.

Here , friction force = 15 N

(ii) Here, applied force = maximum possible value of static friction.

Friction force = 25 N

(iii) Here , applied force > maximum value of static friction.

Therefore , the body moves and kinetic friction acts on the body.

Friction force = μ

k

mg = 20 N.

pls follow me