A body of mass 5kg is placed on the top of a plane inclined 5 degrees with horizontal the lenght of the plane in 5m; the block slides down the plane and reaches the bottom. Find the speed of the block at the bottom if the inclined plane is smooth
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All forces acting on block is shown in figure
Applying equation of motion in X direction
∑FX=max⇒mgsin30−μN=ma⇒a=mgsin30−μNm=mgsin30−μmgcos30m=g(sin30−μcos30)=0.327
So time taken by block to reach the bottom is t and given by
t=√2Sa, where s is the length and a is the acceleration of block
Thus t=√2×6401000.327=6.256s
All forces acting on block is shown in figure
Applying equation of motion in X direction
∑FX=max⇒mgsin30−μN=ma⇒a=mgsin30−μNm=mgsin30−μmgcos30m=g(sin30−μcos30)=0.327
So time taken by block to reach the bottom is t and given by
t=√2Sa, where s is the length and a is the acceleration of block
Thus t=√2×6401000.327=6.256s
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