A body of mass 5kg is suspended by a spring balance on an inclined plane as shown the spring balance measure
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Answered by
56
Thanks for the question. Please find the answer below:
A body of mass 5kg is suspended by a spring balance on an inclined plane as shown in the figure. The spring balance measure is 25N.
Explanation:
As downward force moves along the inclined plane
mgsinθ=5×10×sin30°= 25N
Answered by
10
Hey mate!
Answer: 25N
Explanation:
According to the question: m=5kg and ø=30°
We also know that g=10m/s^2
:. Using equation F=mg sinø
After substituting we get F=25N
Thankyou!
It was a pleasure helping you
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