A body of mass 5kg is suspended by a string from a rigid support. The body is pulled horizontally by a force Funtil the string makes an angle of 60° with the vertical. The value of tension in the string is 50 N 75 N 100 N 25 N
Answers
Answered by
1
Answer:
Explanation:
As the mass is at rest the resultant of forces acting on it are equal to zero
so forces in vertical direction are
T
1
sin30
o
+T
2
sin60
o
−mg=0
2
T
1
+
2
3
T
2
=5g
T
1
+
3
T
2
=100
similarly in horizontal direction
T
1
cos30
o
−T
2
cos60
o
=0
T
2
T
1
=
3
1
solving above equations will give us
T
1
+
3
×
3
T
1
=100
T
1
=25N
T
2
=25
3
N
Answered by
0
A body of mass 5kg is suspended using string making an angle 30∘ and 60∘ with the horizontal then:
A. T1=25 N
B. T2=25 N
C. T1=253–√ N
D. T2=253–√ N
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