Question

A body of mass 5kg is taken from a height of 3m to 6m.Calculate the following:

(i) Initial potential energy.

(ii) Final potential energy.

(iii) The change in total potential energy.​

Answer 1

Given

• Mass = 5 kg
• Initial Height = 3 m
• Final height = 6 m

To Find

• Initial Potential Energy
• Final Potential Energy
• Change in potential energy

Solution

● Potential Energy is given by, P = mgh

✭ Initial Potential Energy

→ P = mgh

→ P (Initial) = 5 × 10 × 3

→ P (Initial) = 150 J

✭ Final Potential Energy

→ P = mgh

→ P (Final) = 5 × 10 × 6

→ P (Final) = 300 J

✭ Change in Potential Energy

→ Final - Initial

→ 300 - 150

→ 150 J

Answer 2

Answer:

Given :-

• A body of mass is 5 kg is taken from a height of 3 m to 6 m.

To Find :-

1. Initial potential energy
2. Final potential energy
3. Change in potential energy

Formula Used :-

❶ To find initial potential energy :

$\boxed{\bold{\small{Initial\: PE\: =\: mgh}}}$

❷ To find final potential energy :

$\boxed{\bold{\small{Final\: PE\: =\: mgh}}}$

❸ To change in total potential energy :

$\boxed{\bold{\small{Change\: in\: PE\: =\: Initial\: PE\: -\: Final\: PE}}}$

Solution :-

Given :

• Mass = 5 kg
• Initial PE height = 3 m
• Final PE height = 6 m
• Acceleration due to gravity (g) = 10 m/s²

❶ Initial potential energy :

⇒ Initial PE = mgh

⇒ Initial PE = 5 × 10 × 3

⇒ Initial PE = 50 × 3

➠ Initial PE = 150 J

❷ Final potential energy :

⇒ Final PE = mgh

⇒ Final PE = 5 × 10 × 6

⇒ Final PE = 50 × 6

➠ Final PE = 300 J

❸ Now, change in total potential energy:

⇒ Change in PE = Final PE - Initial PE

⇒ Change in PE = 300 - 150

➠ Change in PE = 150 J