Question

A body of mass 5kg is thrown up vertically with a kinetic energy of 1000j.If acceleration due to gravityis 10ms-2,find the height at which the kineyic energy becomes half of original value what is the answer

Answer 1

Mass = 5kg

Energy = 1000j = 1000/2 = 500j ( a/q)

Gravity = 10m/s

Height = ?

E = mgh

500 = 5 × 10 × h

=> h = $\frac{500}{5 \times 10} \\ = 10$

Therefore, The height = 10m

Answer 2

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