Physics, asked by Binay11, 1 year ago

A body of mass 5kg is thrown vertically up with a kinetic energy of 490j. The height at which the kinetic energy of the body became half of the orginal value is what?

Answers

Answered by maya30

2

h= 4.9 m

KE=KE/2 + mgh
KE/2 = mgh
490/2= 5x10h
h = 490/(2x5x10) = 4.9

Binay11: thank you dear

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