A body of mass 5kg is thrown vertically up with a kinetic energy of 490j. The height at which the kinetic energy of the body became half of the orginal value is what?
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h= 4.9 m
KE=KE/2 + mgh
KE/2 = mgh
490/2= 5x10h
h = 490/(2x5x10) = 4.9
KE=KE/2 + mgh
KE/2 = mgh
490/2= 5x10h
h = 490/(2x5x10) = 4.9
Binay11:
thank you dear
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