A body of mass 5kg is thrown vertically upwards with a speed of 50m/s. What will be its potential energy at the end of 5 second
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=> h = ut+ 1/2 gt^2
=> h = 50 x 5 + 1/2 x 10 x 5 x 5
=> h = (250 + 125) m
=> h = 375 m
Now,
=> P.E = mgh
=> P.E = (5 x 10 x 375) Joules
=> P.E = 18750 Joules
=> h = 50 x 5 + 1/2 x 10 x 5 x 5
=> h = (250 + 125) m
=> h = 375 m
Now,
=> P.E = mgh
=> P.E = (5 x 10 x 375) Joules
=> P.E = 18750 Joules
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