A body of mass 5kg is under the action of 50N on the horizontal surface.If coefficient of
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43
the answer is 0.9m because
friction acted opposite to the force..
and friction=μmg = 49N
so, now force acted upon the body is
= force - friction
= 50 - 49 N
= 1 N
now,distance travelled in 3 seconds will be
s = 1/2 a t^2
= 1/2 x 1/5 x 3^2
= 0.9 m
friction acted opposite to the force..
and friction=μmg = 49N
so, now force acted upon the body is
= force - friction
= 50 - 49 N
= 1 N
now,distance travelled in 3 seconds will be
s = 1/2 a t^2
= 1/2 x 1/5 x 3^2
= 0.9 m
Answered by
0
Answer:
answer is 0.9 m option 3
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