Question

a body of mass 5kg moves with the velocity of 2 m/s find it's kinetic energy​

Answer 1

Answer:

Given , m=5kg,p=10kg−m/s,

F=0.2N

and t=10s

Let initial momentum be p

p=mu

10=5u

⇒ u=2m/s

From Newton's 2nd law

Acceleration a=

m

F

=

5

0.2

=0.04m/s

2

Final velocity v=u+at

=2+0.04×10

=2.4m/s

Increase in KE=

2

1

m(v

2

−u

2

)

=

2

1

×[(2.4)

2

−(2)

2

]

=4.4J

Answer 2

Answer:

Explanation:

K.E =1/2MV^2

= 1/2×5×2^2

=10

hope this helps you