a body of mass 5kg moving on a horizontal surface with a velocity of 10 ms comes to rest in 2s.the force required to make his body move with a velocity of 10 mson the same surface is?
Sagarika1414:
what do you mean by 10 mson
give a space between ms and on
Answers
Answered by
52
Hi friend
m = 5kg
u = 10m/s
v = 0
t = 2s
F = ma
F = 5 × (0-10/2)
F = 5 × -5
F = -25 N
m = 5kg
u = 10m/s
v = 0
t = 2s
F = ma
F = 5 × (0-10/2)
F = 5 × -5
F = -25 N
tysm
Answered by
8
Answer:
F=25N
Explanation:
F=m(v-u)/t
F=5(0-10)/2
F=5(-10)/2
F=5(-5)
F=-25N
Therefore,F=25N
Similar questions