Question

a body of mass 5kg starts from rest and falls freely. the distance covered by it in one second is.

Answer 1

use s = (g/2)(2n - 1) and put n = 1 ....because initial velocity u = 0
that should do it !

Answer 2

The distance covered by the body in one second is 5m.

Given:-

Mass of body = 5kg

Initial velocity= 0m/s

Time = 1sec

To Find:-

The distance covered by the body in one second.

Solution:-

We can simply calculate the distance covered by the body in one second by using the following method.

As

Mass of body (m) = 5kg

Initial velocity (u) = 0m/s

Time (t) = 1sec

g = 10m/s²

According to the second equation of motion,

$s = ut + \frac{1}{2} g {t}^{2}$

$s = 0 \times 1 + \frac{1}{2} \times 10 \times {1}^{2}$

$s = 5 \times 1$

$s = 5m$

Hence, The distance covered by the body in one second is 5m.

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