Physics, asked by navneet3267, 1 year ago

a body of mass 5kg which is initially at rest is moved by a horizontal force of 10N on a smooth horizontal surface. calculate the work done by the body in 2s

Answers

Answered by Anonymous
2
It depends on how long the force is applied.

F=ma → a = F/m = 2 N / 5 kg = 0.4 m/s2

V= at

E = 1/2 m*V^2 = 0.5*5*(0.4*t)^2 = 0.4*t^2

In 1 second 0.4 Joules is expended. In 10 seconds 40 Joules is expended. In 60 seconds 1.44 kJ is expended.

The associated speeds are 0.4 m/s, 4 m/s, and 24 m/s.

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