a body of mass 5kg which is initially at rest is moved by a horizontal force of 10N on a smooth horizontal surface. calculate the work done by the body in 2s
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It depends on how long the force is applied.
F=ma → a = F/m = 2 N / 5 kg = 0.4 m/s2
V= at
E = 1/2 m*V^2 = 0.5*5*(0.4*t)^2 = 0.4*t^2
In 1 second 0.4 Joules is expended. In 10 seconds 40 Joules is expended. In 60 seconds 1.44 kJ is expended.
The associated speeds are 0.4 m/s, 4 m/s, and 24 m/s.
F=ma → a = F/m = 2 N / 5 kg = 0.4 m/s2
V= at
E = 1/2 m*V^2 = 0.5*5*(0.4*t)^2 = 0.4*t^2
In 1 second 0.4 Joules is expended. In 10 seconds 40 Joules is expended. In 60 seconds 1.44 kJ is expended.
The associated speeds are 0.4 m/s, 4 m/s, and 24 m/s.
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