A body of mass 6.5 kg is acted upon by two
perpendicular forces of 12 N and 5 N. Give the magnitude a direction of acceleration of the body.
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As they are perpendicular to each other therefore according to parallelogram vector addition we need to calculate resulatant force
F =√ 12^2 + 5^ 2. ( as cos 90 = 0)
F = 13 N
Therefore , F =. Ma
a = 13/6.5
= 2m/s^2
Direction of net force = direction of acceleration
Let angle alpha between 12 and 5 N
Therefore tan alpha 12/5 = 2.4
Hence alpha = tan - 2.4
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