A body of mass 6 kg is acted upon
by a force which causes a
12
displacement in it given by x
m
4
where t is the time in second. The
work done by the force in 2 second
is
Answers
Answered by
0
Explanation:
M =6 kg, dis. = x T,=2 sec F=12N
F=ma
12=6a
a=2
s=ut+1/2at`2
x=0×2+1/2×2×2
x=4 W=fs
12×4 =48
Answered by
0
Answer:
W=3j
Explanation:
The displacement of a body is given by x=
4
t
2
∴ Velocity, v=
dt
dx
=
4
1
×2t=
2
t
Initial velocity, u=v
∣
∣
∣
∣
∣
t=0
=0
Final velocity, v=v
∣
∣
∣
∣
∣
t=2
=
2
2
=1 m/s
From work-energy theorem, W=ΔK.E
W=
2
1
mv
2
−
2
1
mu
2
W=
2
1
×6×1
2
−0
⇒ W=3J
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