Question

A body of mass 6 kg is under a force of 6n which cuses a displacement which is given by the formula s=(t^2/4)m.the work done by the force in 2s is

Answer 1

t=2
$s = \frac{2 \times 2}{4} = 1$
$f = ma \\ 6 = 6a \\ a = 1$

f=6n and m=6kg
$w = fs \\ w = 6 \times 1 \\ w = 6$

work equal to 6 joule