Question

a body of mass 6 kg travelling with a v elocity 10 m/s collides head on and elastically 5m/s in opposite direction the velocity of the second body after the collision is
​

Answer 1

Answer:

13meters per second

Explanation:

m₁ = 6kg

u₁ = 10m/s

m₂ = 4 kg

u₂ = -5 m/s

v₂ = ?

\begin{gathered}v_2= \frac{u_2(m_2-m_1)+2m_1u_1}{m_1+m_2} \\ \\ \Rightarrow v_2= \frac{-5(4-6)+2 \times 6 \times 10}{4+6} \\ \\ \Rightarrow v_2= \frac{10+120}{10} \\ \\ \Rightarrow v_2= 13\ m/s\end{gathered}

v

2

=

m

1

+m

2

u

2

(m

2

−m

1

)+2m

1

u

1

⇒v

2

=

4+6

−5(4−6)+2×6×10

⇒v

2

=

10

10+120

⇒v

2

=13 m/s