Question

A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.A body of mass 60 kg is moving with a constant velocity of 13m/s. If the force of 72N is apllied on the base of the object then what would be the parabolic equation made by the body and maximum height.

Answer 1

Answer:

Net force acting on the body =(μ

s

−μ

k

) mg

Acceleration =(μ

s

−μ

k

)g=0.1×9.8=0.98ms

−2

Answer 2

Answer:

Net force acting on the body =(μs −μk ) mg

Acceleration =(μs −μk )g=0.1×9.8=0.98ms−2

take care beautiful!♥⭐