A body of mass 60 Kg is pushed with just enough horizontal force to start it moving on a rough horizontal surface with coefficient static friction 0.5 and coefficient of kinetic friction 0.4 and the force continue to act afterwards , the time taken to acquire a velocity of 5 m/ s is ( g= 10 m/ s* 2) a) 5 s. b) 2.5 s. c) 10 s d) 4 s
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Explanation:
Correct option is
C
1m/s
2
The Uniting friction =μ
s
R
μ
s
mg=0.5×60×10=300N
Kinetic friction =μ
k
R=μ
k
mg
=0.4×60×10=240N
Force applied = 300 N
Net accelerating force
= Applied force - kinetic friction
⇒ ma = 300 - 240 = 60
⇒a=
60
60
=1m/s
2
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