Question

a body of mass 600 grams is at rest on a frictionless surface calculate the distance travelled by it in 20 seconds when acted upon by a force of 10^-2 Newton​

Answer 1

Given :

• Initial velocity, u = 0 m/s (as it is at rest)
• Time taken, t = 20 seconds
• Force acted on the body, F = 10² N = 0.01 N
• Mass of a body, m = 600 g = 0.6 kg

To find :

• Distance travelled, s

According to the question,

➞ F = ma

Where,

• F = Force
• a = Acceleration
• m = Mass

➞ Substituting the values,

➞ 0.01 = 0.6 × a

➞ 0.01 ÷ 0.6 = a

➞ 0.0167 = a

So,the acceleration is 0.0167 m/s².

Now,

We will find distance travelled by using Newtons third equation of motion,

➞ s = ut + ½ at²

Where,

• s = Distance travelled
• u = Initial velocity
• a = Acceleration
• t = Time

➞ Substituting the values,

➞ s = 0 × 20 + ½ × 0.0167 × 20 × 20

➞ s = 0 + 0.0167 × 10 × 20

➞ s = 0 + 3.34

➞ s = 3.34

So,the distance travelled by the body is 3.34 meters.

Answer 2

Given:-

$\star$The body of mass 600 gram is resting on a frictionless surface.

To Prove:-

$\star$We have to find distance travelled by it in 20 seconds when acted upon by a force of 10-² N.

Solution:-

$\star$Mass of body (m) = 600 gram = 600/1000 = 0.6 kg.

$\star$Initial speed (u) = 0 m/s (As it starts from rest).

$\star$Force acting (F) = 10-² N = 0.01 N.

$\star$Using Formula,

$\star\large{ \boxed{ \boxed{ \frak{ \purple{force = mass \times accleration}}}}}$

$\star$Substitute the given value in formula,

$\longrightarrow \:{ \frak{0.01 = 0.06 \times a}}$

$\\ \longrightarrow \:{ \frak{a = \frac{0.01}{0.6} }}$

$\longrightarrow \:{ \frak{ = 0.0167 \: m/s {}^{2} + a}}$

$\star$.. Acceleration of body = 0.0167 m/s²

$\star$From the 2nd equation of motion :-

$\star$Using formula,

$\star\large{ \boxed{ \boxed{ \frak{ \purple{s = ut + \frac{1}{2} \times at {}^{2}}}}}}$

$\star$Substitute the values in formula,

$\\ \longrightarrow \:{ \frak{s = 0 \times 20 + \frac{1}{2} \times 0.067 \times 20 {}^{2} }}$

$\\ \longrightarrow \:{ \frak{s = 0 + 0.0167 \times 10 \times 20}}$

$\\ \longrightarrow \:{ \frak{s = 0 + 3.34}}$

$\\ \longrightarrow \:{ \boxed{ \boxed{ \frak{s = 3.34}}}}$

$\star$Distance travelled by the body is 3.34 meters.