Question

A body of mass 6kg has an initial speed 4ms". A foce acts on it for some
time in the direction of motion. The force-time graph is shown in figure.
Find the final speed of the body

Answer 1

Answer:

ANSWER

We know,

Area under force-time graph = change in linear momentum

∴ΔP=

2

1

×2×4+(4−2)×4+(4.5−4)×2.5+

2

1

×(4.5−4)(4−2.5)+(6.5−4.5)×2.5

∴P

f

−P

i

=18.625

Now,

P

i

=m×v

i

=2×5=10kgm/s

∴P

f

=10+18.625

∴P

f

=28.625kgms

−1

∴v

f

=14.3125m/s