Question

A body of mass 6kg immerses in water partially.If the body displaces 100g of water then the apparent weight of the body is?

Answer 1

Answer:

5 kg 900 g is the apparent mass of body. then you can find its weight by formula. w=mg. where mass =5kg 900g and g =9.8

Answer 2

The apparent weight of the body is 59 N .

Given :

Mass of body , M = 6 kg .

Water displaced by body , m = 100 gm = 0.1 kg .

Therefore , apparent mass is , $M'=M-m = 6-0.1 =5.9\ kg .$

Now , we are required to find the apparent weight of the body .

We know , weight is given as :

W = mg ,

( Here g is acceleration due to gravity and given by $g = 10\ m/s^2$ . )

Putting apparent weight in above equation , we get :

$W=5.9\times 10\\W=59\ N.$

Therefore , apparent weight of the body is 59 N .

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Apparent Mass

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