Question

A body of mass 6kg is dropped from a height of 5m what is the average force applied by the ground

Answer 1

Answer:

Given-m=50gm

h=10m

Δt=0.01sec

Let the ball strike with the velocity v.

Since it losses 75% of the total kinetic energy, it means that it has only 25% of its total energy.

Since KE is proportional to v

2

, it means that the velocity with which it leaves the ground is

2

v

.

So Impulse=

(time)

(change in momentum)

Change in momentum=mv

2

−0.5×mv

2

=0.5×mv

2

So,

v=

2gh

=

200

=10

2

ms

−1

Change in momentum=0.5×mv

2

Impulse=

times(0.01)

(0.5)×(0.05)(10

2

)

2

Impulse=1.0534N−s