a body of mass 6kg is made to fa freely from a height of 18m.find its mechanical energy when it travels 1/3rd distance.
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aswer is 3960 joule
i hope it helps
i hope it helps
Manasa2003:
send me the method
Answered by
1
Hi friend,
We know that ,
Mechanical energy= potential energy+kinetic energy
Potential energy= mgh
= 6×10×6(18/3)
Potential energy= 3600J
Kinetic energy= 1/2 mv²
V²=u²+2as
V²= 2×10×6
V²= 120m/s.
Kinetic energy= 1/2×6×120
Kinetic energy= 360J
Mechanical energy= 3600+360
Mechanical energy= 3960J.
Hope this helped you a little!!!
We know that ,
Mechanical energy= potential energy+kinetic energy
Potential energy= mgh
= 6×10×6(18/3)
Potential energy= 3600J
Kinetic energy= 1/2 mv²
V²=u²+2as
V²= 2×10×6
V²= 120m/s.
Kinetic energy= 1/2×6×120
Kinetic energy= 360J
Mechanical energy= 3600+360
Mechanical energy= 3960J.
Hope this helped you a little!!!
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