Question

A body of mass 6kg makes an elastic collision with another body at rest and continues to move in the original direction with 1/2 of its original speed . Then the mass of 2nd body is approximately....

Answer 1

Since collision is elastic, energy and momentum both are conserved.

Let mass of 1st object be m1 and second object be m2.

Let initial velocity of 1st object be v1 and second is initially at rest. Let final velocity of m2 be v2.

So m1v1=m1(v1/2)+m2v2.(momentum conservation)

0.5×m1×v1^2=0.5×m1*v1^2/4+0.5×m2×v2^2.(energy conservation).

Solve these 2 equations. Write v2 in terms of m1,v1,m2 from first equations and substitute it in the second.

You get v2=m1×v1/(2×m2)

And you obtain m1=3m2.

Thus m2=m1/3=6/3=2kg.

Cheers Mark brainliest Sub to pewds.

LBM.

Answer 2

Answer:

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